Index

Geometry of solids

Volume and surface area

Hint: In all following exercises it's a good idea to draw the solid first.
  1. ?
    ?
    Volume of a cuboid with length , width w and height h is:

    V=wh
    A cuboid has the length =18 cm, width w=10 cm and heigth h=25 cm.

    (a)   Find the volume.

    (b)   Find the surface area.

    (c)   Calculate the space diagonal.

    Solutions:    (a)  V=4500 cm3;     (b)  A=1760 cm2;     (c)  D32.4 cm
  2. A cuboid has =w=4 cm, h=7 cm.

    (a)   Find the volume.

    (b)   Find the space diagonal.

    (c)   Calculate the angle between the space diagonal and the diagonal of the base.

    Solutions:    (a)  V=112 cm3;     (b)  D=9 cm;     (c)  φ51.1
  3. A cube has =w=h=10 cm.

    (a)   Find the volume.

    (b)   Find the surface area.

    Solutions:    (a)  V=1000 cm3;     (b)  A=600 cm2
  4. A cube has the volume V=3375 cm3.

    (a)   Find the edge.

    (b)   Find the surface area.

    Solutions:    (a)  =w=h=15 cm3;     (b)  A=1350 cm2
  5. ?
    ?
    Volume of a prism with base area A and height h is:

    V=Ah
    A three-sided right prism has the height h=12 cm. The base of this prism is a triangle with sides a=13 cm, b=11 cm, c=20 cm.

    (a)   Find the area of the base.

    (b)   Find the volume of this prism.

    (c)   Find the surface area of this prism.

    Solutions:    (a)  ABASE=66 cm2;     (b)  V=792 cm3;     (c)  ATOTAL=660 cm2
  6. A three-sided right prism has the height h=9 cm. The base of this prism is a triangle with sides a=8 cm, b=15 cm and c=17 cm.

    (a)   Find the volume of this prism.

    (b)   Find the total surface area of this prism.

    Solutions:    (a)  V=540 cm3;     (b)  ATOTAL=480 cm2
  7. A three-sided right prism has the height h=11 cm. The base of this prism is an isosceles triangle with sides a=b=15 cm and c=18 cm.

    (a)   Find the area of the base.

    (b)   Find the volume of this prism.

    (c)   Find the total surface area of this prism.

    Solutions:    (a)  ABASE=108 cm2;     (b)  V=1188 cm3;     (c)  ATOTAL=744 cm2
  8. A regular three-sided prism has the height h=7 cm. The base of this prism is an equilateral triangle with sides equal to a=15 cm.

    (a)   Find the area of the base.

    (b)   Find the volume of this prism.

    (c)   Find the total surface area of this prism.

    Solutions:    (a)  ABASE97.4 cm2;     (b)  V682 cm3;     (c)  ATOTAL510 cm2
  9. A regular three-sided prism has the height h=7.3 cm and the base edge a=8.4 cm.

    (a)   Find the volume of this prism.

    (b)   Find the total surface area of this prism.

    Solutions:    (a)  V223 cm3;     (b)  ATOTAL245 cm2
  10. A regular six-sided prism has the height h=10 cm and the base edge a=8 cm.

    (a)   Find the volume of this prism.

    (b)   Find the total surface area of this prism.

    Solutions:    (a)  V1660 cm3;     (b)  ATOTAL813 cm2
  11. An uniform regular six-sided prism has the edge a=7 cm.

    (a)   Find the volume of this prism.

    (b)   Find the surface area of this prism.

    Solutions:    (a)  V891 cm3;     (b)  ATOTAL549 cm2
  12. A uniform regular six-sided prism has the volume of 1 litre. Find the base edge of this prism.
    Solution:    a7.27 cm
  13. ?
    ?
    Volume of a cylinder with radius r and height h is:

    V=πr2h

    Area of the curved surface of a cylinder with radius r and height h is:

    A=2πrh
    A cylinder has the radius r=7 cm and height h=9 cm.

    (a)   Find the volume of this cylinder.

    (b)   Find the area of the base.

    (c)   Find the area of the curved surface.

    (d)   Find the total surface area of this cylinder.

    Solutions:    (a)  V1385 cm3;     (b)  ABASE154 cm2;     (c)  ACURVED396 cm2;     (d)  ATOTAL704 cm2
  14. A cylinder has the radius r=2 cm and height h=19 cm.

    (a)   Find the volume of this cylinder.

    (b)   Find the total surface area of this cylinder.

    Solutions:    (a)  V239 cm3;     (b)  ATOTAL264 cm2
  15. ?
    ?
    Volume of a right pyramid with base area A and height h is:

    V=13Ah
    A right pyramid with a square base has the base edge a=12 cm and the height h=15 cm. Find the volume of this pyramid.
    Solution:    V=720 cm3
  16. A right pyramid has the height h=18 cm. The base of this pyramid is a triangle with sides a=13 cm, b=14 cm, c=15 cm. Find the volume of this pyramid.
    Solution:    V=504 cm3
  17. A three-sided pyramid has the height h=20 cm. The base of this pyramid is an isosceles triangle with sides a=b=25 cm, c=14 cm. Find the volume of this pyramid.
    Solution:    V=1120 cm3
  18. A four-sided pyramid has the height h=16 cm. The base of this pyramid is a rectangle with sides a=12 cm, b=8 cm. Find the volume of this pyramid.
    Solution:    V=512 cm3
  19. A square right pyramid has the base edge a=10 cm and the height h=12 cm.

    (a)   Find the area of the base.

    (b)   Find the volume of this pyramid.

    (c)   Find the slant height (height of a lateral face).

    (d)   Find the area of a lateral face.

    (e)   Find the total surface area of this pyramid.

    Solutions:    (a)  ABASE=100 cm2;     (b)  V=400 cm3;     (c)  hSLANT=13 cm;     (d)  ALATERAL=65 cm2;     (e)  ATOTAL=360 cm2
  20. A regular four-sided right pyramid has the base edge a=14 cm and the height h=24 cm.

    (a)   Find the volume of this pyramid.

    (b)   Find the area of a lateral face.

    (c)   Find the total surface area of this pyramid.

    Solutions:    (a)  V=1568 cm3;     (b)  ALATERAL=175 cm2;     (c)  ATOTAL=896 cm2
  21. A square right pyramid has the base edge a=32 cm and the lateral edge e=34 cm.

    (a)   Find the area of a lateral face.

    (b)   Find the total surface area of this pyramid.

    (c)   Find the height of this pyramid.

    (d)   Find the volume of this pyramid. Express the volume in litres.

    Solutions:    (a)  ALATERAL=480 cm2;     (b)  ATOTAL=2944 cm2;     (c)  h25.4 cm;     (d)  V8.66 
  22. A regular four-sided pyramid has the base edge a=18 cm and the lateral edge e=41 cm. Find the surface area of this pyramid.
    Solution:    ATOTAL=1764 cm2
  23. An uniform regular four-sided pyramid has the edge a=10 cm. Find the surface area of this pyramid.
    Solution:    ATOTAL273 cm2
  24. An uniform regular three-sided pyramid has the edges a=e=12 cm. Find the surface area of this pyramid.
    Solution:    ATOTAL249 cm2
  25. ?
    ?
    Volume of a cone with radius r and height h is:

    V=13πr2h

    Area of the curved surface of a cone with radius r, height h and slant height is:

    A=πr     where   =r2+h2
    A cone has the radius r=5 cm and the height h=12 cm.

    (a)   Find the volume of this cone.

    (b)   Find the slant height of this cone.

    (c)   Find the total surface area of this cone.

    Solutions:    (a)  V=100π cm3314 cm3;     (b)  =13 cm;     (c)  ATOTAL=90π cm2283 cm2
  26. A cone has the radius r=5 cm and the slant height =12 cm.

    (a)   Find the height of this cone.

    (b)   Find the volume of this cone.

    (c)   Find the total surface area of this cone.

    Solutions:    (a)  h10.9 cm;     (b)  V286 cm3;     (c)  ATOTAL=85π cm2267 cm2
  27. ?
    ?
    Volume of a sphere with radius r is:

    V=43πr3

    Surface area of a sphere with radius r is:

    A=4πr2
    A sphere has the radius r=3 cm.

    (a)   Find the volume of this sphere.

    (b)   Find the surface area of this sphere.

    Solutions:    (a)  V=36π cm3113 cm3;     (b)  A=36π cm2113 cm2
  28. A sphere has the volume V=1  (one litre =1000 cm3).

    (a)   Find the raduis.

    (b)   Find the surface area of this sphere.

    Solutions:    (a)  r6.20 cm;     (b)  A484 cm2
  29. Earth is (approximately) a sphere. Its circumference is the length of equator =40000 km.

    (a)   Find the radius of Earth.

    (b)   Find the surface area of Earth.

    Russia is the largest state in the world and its area is 17098246 km2.

    (c)   Calculate how many percent of the surface of Earth lies in Russia.

    Solutions:    (a)  r6366 km;     (b)  A5.09108 km2;     (c)  3.36%

Angles in solids

Find a right-angled triangle in the given solid and then use trigonometric functions to find the angle.
  1. A cuboid has =w=6 cm, h=17 cm.

    (a)   Find the space diagonal.

    (b)   Find the angle between the space diagonal and lateral edge.

    (c)   Find the angle between the space diagonal and the base of this cuboid.

    Solutions:    (a)  D=19 cm;     (b)  α26.5;     (c)  φ63.5
  2. Calculate the angle between the space diagonal and the base of a cube.
    Solution:    φ35.3
  3. A square right pyramid has the base edge a=12 cm and the lateral edge e=11 cm.

    (a)   Find the height of this pyramid.

    (b)   Find the angle between the lateral edge and the base.

    (c)   Find the angle between two adjacent lateral edges.

    Solutions:    (a)  h=7 cm;     (b)  φ39.5;     (c)  ψ66.1
  4. A square pyramid has all base edges and lateral edges of the same length: a=e=10 cm.

    (a)   Find the angle between the lateral edge and the base edge of the pyramid.

    (b)   Find the angle between the lateral edge and the base of the pyramid.

    Solutions:    (a)  α=60;     (b)  φ=45
  5. A square right pyramid has the base edge a=14 cm and the height h=24 cm.

    (a)   Find the angle between the slant height and the height.

    (b)   Find the angle between the lateral edge and the height.

    Solutions:    (a)  α16.3;     (b)  β22.4
  6. A cone has the radius r=9 cm and height h=12 cm.

    (a)   Find the slant height of this cone.

    (b)   Find the angle between the slant height and the base of this cone.

    (c)   Find the opening angle (the angle between two opposite slant heights).

    Solutions:    (a)  =15 cm;     (b)  φ53.1;     (c)  θ73.7

Solids in real life situations

  1. Our town is building a swimming pool which has the shape of a cuboid with length of 50 m, width of 25 m and depth of 2.5 m. The bottom and lateral sides are covered in ceramic tiles. One square meter of these tiles costs 7.20 €.

    (a)   Find the surface area of the bottom and lateral sides.

    (b)   Calculate the cost of the ceramic tiles.

    When the pool is complete, they start filling it with water. They use a hose with water flow of 15 litres per second. They stop filling it when the water level is 25 cm below the upper edge of the pool.

    (c)   Find the volume of water in litres.

    (d)   Calculate the time necessary to fill the pool up to this level.

    Solutions:    (a)  A=1625 m2;     (b)  cost = 11 700 €     (c)  V=2812.5 m3=2812500 ;     (d)  52 hours (approximately)
  2. Farmer has a silo for storing corn. This silo has the form of a vertical cylinder with the diameter of 4 m and height of 5 m. The silo is filled up to one half of its height.

    (a)   Find the total volume of this silo.

    (b)   Calculate the mass of corn (in kg), if you know that one liter of corn has the weight of 0.91 kg.

    Farmer has a ladder, which is 515 cm long. He puts it to the silo, so that the top of the ladder is aligned with the top of the silo.

    (c)   How far apart are the bottom of the silo and the bottom of the ladder?

    (d)   Calculate the angle of elevation of this ladder.

    Solutions:    (a)  V=62.832 m3=62832 ;     (b)  m=28588 kg;     (c)  x=123.4 cm;     (d)  α=76.1
  3. A town is planning the Christmas decorations. They bought 480 plastic balls with radius of 7 cm and they want to colour them with gold colour. Now they are planning to buy several cans of gold colour. Each can contains 1 kg of gold colour. One gram of gold colour covers 30 cm2.

    (a)   Find the surface of one ball.

    (b)   Calculate, how much colour is required for one ball.

    (c)   Find out, how many cans will they need for all 480 balls.

    Solutions:    (a)  A=615.75 cm2;     (b)  20.5 g;     (c)  9852 g means 10 cans at 1kg
  4. Green peas Green peas are sold in a can which has the form of a cylinder. The diameter of this cylinder is 7 cm and the height is 11 cm. Each single pea has the form of a sphere with the diameter 7 mm.

    (a)   Find the volume of the can.

    (b)   Find the volume of a single pea.

    (c)   Find out how many peas are there in the can, knowing that peas represent 85% of the volume of the can.

    Solutions:    (a)  VCAN=423 cm3;     (b)  VPEA=0.180 cm3;     (c)  this can contains 2000 peas (approximately)

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